Physics Jamb Questions
1. The inner diameter of a test tube can be measured accurately using a
- A. micrometer screw guage
- B. pair of dividers
- C. metre rule
- D. pair of vernier calipers
Correct Answer: Option D
2. Two bodies have masses in the ratio 3:1. They experience forces which impart to them acceleration in the ratio 2:9 respectively. Find the ratio of forces the masses experienced.
- A. 1 : 4
- B. 2 : 1
- C. 2 : 3
- D. 2 : 5
Correct Answer: Option C
Explanation
Let the forces be F1, and F2.F1 = m1 a1 = 3 x 2 = 6N
F2 = m2 a2 = 1 x 9 = 9N
F1 : F2 = 6:9 = 2:3
Thus ratio of forces is 2:3
3. Particles of mass 10^-2kg is fixed to the tip of a fan blade which rotates with angular velocity of 100rad-1. If the radius of the blade is 0.2m, the centripetal force is
- A. 2 N
- B. 20 N
- C. 200 N
- D. 400 N
Correct Answer: Option B
Explanation
F =(Since V = ωr)
F = 10
x 100 x 0.2
F =20 N
4. a lead bullet of mass 0.05kg is fired with a velocity of 200ms-1 into a lead block of mass 0.95kg. Given that the lead block can move freely, the final kinetic energy after impact is
- A. 50 J
- B. 100 J
- C. 150 J
- D. 200 J
Correct Answer: Option A
Explanation
From principle of conservation of linear momentum,(0.05 x 200) - (0.95 x 0) = (0.05 + 0.95) x V (since collision is inelastic).
Thus V = 10m/s.
K.E = 1/2 (0.05 + 0.95) x 102
K.E = 1/2 (1 x 100) = 50 J
5. A ball of mass 0.1kg is thrown vertically upwards with a speed of 10ms-1 from the top of a tower 10m high. Neglecting air resistance, its total energy just before hitting the ground is
(take g = 10ms-2)
Energy before hitting ground is = P.E at the height of 15m.
P.E = mgh = 0.1 x 10 x 15 = 15 J
6. A car of mass 800kg attains a speed of 25m/s in 20 secs. The power developed in the engine is
=
= 2.5 x 10
watts
(take g = 10ms-2)
- A. 5 J
- B. 10 J
- C. 15 J
- D. 20 J
Correct Answer: Option C
Explanation
Height h = 1/2 (U2/g) = 102/20 = 5mEnergy before hitting ground is = P.E at the height of 15m.
P.E = mgh = 0.1 x 10 x 15 = 15 J
6. A car of mass 800kg attains a speed of 25m/s in 20 secs. The power developed in the engine is
- A. 1 . 25 x 104 W
- B. 2 . 50 x 104 W
- C. 1 . 25 x 106W
- D. 2 . 50 x 106 W
Correct Answer: Option B
Explanation
Power = Force x= 2.5 x 10
watts
7.
When the brakes in a car are applied, the frictional force force on the tyres is
- A. is a disadvantage because it is in the direction of the motion of the car
- B. is a disadvantage because it is in the opposite direction of the motion of the car
- C. is an advantage because it is in the direction of the motion of the car
- D. is an advantage because it is in the opposite direction of the motion of the car
Correct Answer: Option D
8. If the stress on a wire is 107NM-2 and the wire is stretched from its original length of 10.00 cm to 10.05 cm. The young's modulus of the wire is
Strain = e/l0. = (10.05 - 10.00)/10.00 = 0.005
Thus Y = 107/0.005 = 2 . 0 x 109Nm-2
- A. 5 . 0 x 104 Nm-2
- B. 5 . 0 x 105 Nm-2
- C. 2 . 0 x 108 Nm-2
- D. 2 . 0 x 109 Nm-2
Correct Answer: Option D
Explanation
Y = stress/strain, but stress = 107Nm-2 (given).Strain = e/l0. = (10.05 - 10.00)/10.00 = 0.005
Thus Y = 107/0.005 = 2 . 0 x 109Nm-2
9 When temperature of a liquid increases, its surface tension
- A. Decreases
- B. Increases
- C. Remain Constant
- D. Increases then decreases
Correct Answer: Option A
10 .A solid weigh 10 .00 N in air, 6 N when fully immersed in water and 7
. 0 N when fully immersed in a liquid X. Calculate the relative density
of the liquid, X.
R.D = (10 - 7)/(10 - 6) = 3/4
- A. 5/3
- B. 4/3
- C. 3/4
- D. 7/10
Correct Answer: Option C
Explanation
R.D = loss in weight in liquid X loss in weight in water.R.D = (10 - 7)/(10 - 6) = 3/4
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